6x^2+3x-300=0

Solution for 6x^2+3x-300=0 equation:

6x^2+3x-300=0

a = 6; b = 3; c = -300;
Δ = b2-4ac
Δ = 32-4·6·(-300)
Δ = 7209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7209}=\sqrt{81*89}=\sqrt{81}*\sqrt{89}=9\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9\sqrt{89}}{2*6}=\frac{-3-9\sqrt{89}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9\sqrt{89}}{2*6}=\frac{-3+9\sqrt{89}}{12}
$